Base | Representation |
---|---|
bin | 100011011110011001000011… |
… | …0110010101101100111110001 |
3 | 1111220211202100211021020222100 |
4 | 1012330302012302231213301 |
5 | 311344431340202230001 |
6 | 3023353144532531013 |
7 | 122504106451143525 |
oct | 10674620662554761 |
9 | 1456752324236870 |
10 | 312040225430001 |
11 | 90475575424252 |
12 | 2abb75a0180a69 |
13 | 10516361796093 |
14 | 570ab82903d85 |
15 | 2611d37e45586 |
hex | 11bcc86cad9f1 |
312040225430001 has 24 divisors (see below), whose sum is σ = 453543530454560. Its totient is φ = 206726152185216.
The previous prime is 312040225429997. The next prime is 312040225430023. The reversal of 312040225430001 is 100034522040213.
312040225430001 is a `hidden beast` number, since 3 + 1 + 2 + 0 + 4 + 0 + 225 + 430 + 0 + 0 + 1 = 666.
It is not a de Polignac number, because 312040225430001 - 22 = 312040225429997 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (312040225430041) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 139816 + ... + 24981993.
Almost surely, 2312040225430001 is an apocalyptic number.
It is an amenable number.
312040225430001 is a deficient number, since it is larger than the sum of its proper divisors (141503305024559).
312040225430001 is a wasteful number, since it uses less digits than its factorization.
312040225430001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25130445 (or 25130442 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 312040225430001 its reverse (100034522040213), we get a palindrome (412074747470214).
The spelling of 312040225430001 in words is "three hundred twelve trillion, forty billion, two hundred twenty-five million, four hundred thirty thousand, one".
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