Search a number
-
+
31209000143 = 43725790701
BaseRepresentation
bin11101000100001100…
…111000110011001111
32222120000020110210012
4131010030320303033
51002404001001033
622200501103435
72153250060416
oct350414706317
988500213705
1031209000143
1112265737802
12606b9b7b7b
132c349bacb9
141720c3c47d
15c29d41248
hex744338ccf

31209000143 has 4 divisors (see below), whose sum is σ = 31934790888. Its totient is φ = 30483209400.

The previous prime is 31209000139. The next prime is 31209000149. The reversal of 31209000143 is 34100090213.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34100090213 = 74871441459.

It is a cyclic number.

It is not a de Polignac number, because 31209000143 - 22 = 31209000139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31209000149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 362895308 + ... + 362895393.

It is an arithmetic number, because the mean of its divisors is an integer number (7983697722).

Almost surely, 231209000143 is an apocalyptic number.

31209000143 is a deficient number, since it is larger than the sum of its proper divisors (725790745).

31209000143 is an equidigital number, since it uses as much as digits as its factorization.

31209000143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 725790744.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 31209000143 its reverse (34100090213), we get a palindrome (65309090356).

The spelling of 31209000143 in words is "thirty-one billion, two hundred nine million, one hundred forty-three", and thus it is an aban number.

Divisors: 1 43 725790701 31209000143