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312113010301 = 2852831094047
BaseRepresentation
bin1001000101010110110…
…00101001011001111101
31002211121200200201002021
410202223120221121331
520103201412312201
6355214401000141
731356310546231
oct4425330513175
91084550621067
10312113010301
11110403726214
12505a6023051
1323580510a21
141116bb7a5c1
1581bad03ea1
hex48ab62967d

312113010301 has 4 divisors (see below), whose sum is σ = 312114389632. Its totient is φ = 312111630972.

The previous prime is 312113010289. The next prime is 312113010329. The reversal of 312113010301 is 103010311213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 312113010301 - 25 = 312113010269 is a prime.

It is a super-2 number, since 2×3121130103012 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312113010101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261741 + ... + 832306.

It is an arithmetic number, because the mean of its divisors is an integer number (78028597408).

Almost surely, 2312113010301 is an apocalyptic number.

It is an amenable number.

312113010301 is a deficient number, since it is larger than the sum of its proper divisors (1379331).

312113010301 is a wasteful number, since it uses less digits than its factorization.

312113010301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1379330.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 312113010301 its reverse (103010311213), we get a palindrome (415123321514).

The spelling of 312113010301 in words is "three hundred twelve billion, one hundred thirteen million, ten thousand, three hundred one".

Divisors: 1 285283 1094047 312113010301