Base | Representation |
---|---|
bin | 100011011110111010111111… |
… | …0011101111110111000110011 |
3 | 1111221002201110121001021002210 |
4 | 1012331311332131332320303 |
5 | 311402130112124101003 |
6 | 3023450440120343203 |
7 | 122512266403514133 |
oct | 10675657635767063 |
9 | 1457081417037083 |
10 | 312113100222003 |
11 | 904a3471338083 |
12 | 2b009739914b03 |
13 | 105201a6696692 |
14 | 57104d724cac3 |
15 | 2613ba0b16503 |
hex | 11bdd7e77ee33 |
312113100222003 has 32 divisors (see below), whose sum is σ = 434362540829184. Its totient is φ = 198974463950592.
The previous prime is 312113100221929. The next prime is 312113100222029. The reversal of 312113100222003 is 300222001311213.
It is not a de Polignac number, because 312113100222003 - 29 = 312113100221491 is a prime.
It is a super-3 number, since 3×3121131002220033 (a number of 44 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (312113100221003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4201073325 + ... + 4201147617.
It is an arithmetic number, because the mean of its divisors is an integer number (13573829400912).
Almost surely, 2312113100222003 is an apocalyptic number.
312113100222003 is a deficient number, since it is larger than the sum of its proper divisors (122249440607181).
312113100222003 is a wasteful number, since it uses less digits than its factorization.
312113100222003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90075.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 312113100222003 its reverse (300222001311213), we get a palindrome (612335101533216).
The spelling of 312113100222003 in words is "three hundred twelve trillion, one hundred thirteen billion, one hundred million, two hundred twenty-two thousand, three".
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