Base | Representation |
---|---|
bin | 1001000101010110110… |
… | …10100111000110010111 |
3 | 1002211121201122212022111 |
4 | 10202223122213012113 |
5 | 20103202030301033 |
6 | 355214420011451 |
7 | 31356315122230 |
oct | 4425332470627 |
9 | 1084551585274 |
10 | 312113525143 |
11 | 110403a48002 |
12 | 505a6230b87 |
13 | 23580661174 |
14 | 1116bc72087 |
15 | 81bada67cd |
hex | 48ab6a7197 |
312113525143 has 4 divisors (see below), whose sum is σ = 356701171600. Its totient is φ = 267525878688.
The previous prime is 312113525137. The next prime is 312113525173. The reversal of 312113525143 is 341525311213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 312113525143 - 213 = 312113516951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312113525173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22293823218 + ... + 22293823231.
It is an arithmetic number, because the mean of its divisors is an integer number (89175292900).
Almost surely, 2312113525143 is an apocalyptic number.
312113525143 is a deficient number, since it is larger than the sum of its proper divisors (44587646457).
312113525143 is an equidigital number, since it uses as much as digits as its factorization.
312113525143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44587646456.
The product of its digits is 10800, while the sum is 31.
Adding to 312113525143 its reverse (341525311213), we get a palindrome (653638836356).
The spelling of 312113525143 in words is "three hundred twelve billion, one hundred thirteen million, five hundred twenty-five thousand, one hundred forty-three".
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