Base | Representation |
---|---|
bin | 1110001100011000111000… |
… | …01110111000101001101111 |
3 | 11002111211122000102001020111 |
4 | 13012030130032320221233 |
5 | 13042334134224113033 |
6 | 150214332331000451 |
7 | 6400664324060431 |
oct | 706143416705157 |
9 | 132454560361214 |
10 | 31212001004143 |
11 | 9a43a31965193 |
12 | 3601117b99127 |
13 | 145538215082b |
14 | 79c9516b4651 |
15 | 391d683827cd |
hex | 1c631c3b8a6f |
31212001004143 has 4 divisors (see below), whose sum is σ = 31639562661808. Its totient is φ = 30784439346480.
The previous prime is 31212001004117. The next prime is 31212001004299. The reversal of 31212001004143 is 34140010021213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31212001004143 - 213 = 31212000995951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31212001104143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213780828723 + ... + 213780828868.
It is an arithmetic number, because the mean of its divisors is an integer number (7909890665452).
Almost surely, 231212001004143 is an apocalyptic number.
31212001004143 is a deficient number, since it is larger than the sum of its proper divisors (427561657665).
31212001004143 is an equidigital number, since it uses as much as digits as its factorization.
31212001004143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 427561657664.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 31212001004143 its reverse (34140010021213), we get a palindrome (65352011025356).
The spelling of 31212001004143 in words is "thirty-one trillion, two hundred twelve billion, one million, four thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •