Base | Representation |
---|---|
bin | 1110001100011000111010… |
… | …00000101011000001010001 |
3 | 11002111211122220222010100021 |
4 | 13012030131000223001101 |
5 | 13042334201044234010 |
6 | 150214333514423441 |
7 | 6400664543026153 |
oct | 706143500530121 |
9 | 132454586863307 |
10 | 31212014055505 |
11 | 9a43a39269938 |
12 | 3601120431b81 |
13 | 1455384a7022a |
14 | 79c953310ad3 |
15 | 391d695ae8da |
hex | 1c631d02b051 |
31212014055505 has 16 divisors (see below), whose sum is σ = 37707109300224. Its totient is φ = 24801484875840.
The previous prime is 31212014055503. The next prime is 31212014055553. The reversal of 31212014055505 is 50555041021213.
It is not a de Polignac number, because 31212014055505 - 21 = 31212014055503 is a prime.
It is a super-3 number, since 3×312120140555053 (a number of 41 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31212014055503) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20208049 + ... + 21697678.
It is an arithmetic number, because the mean of its divisors is an integer number (2356694331264).
Almost surely, 231212014055505 is an apocalyptic number.
It is an amenable number.
31212014055505 is a deficient number, since it is larger than the sum of its proper divisors (6495095244719).
31212014055505 is a wasteful number, since it uses less digits than its factorization.
31212014055505 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41906736.
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 31212014055505 its reverse (50555041021213), we get a palindrome (81767055076718).
The spelling of 31212014055505 in words is "thirty-one trillion, two hundred twelve billion, fourteen million, fifty-five thousand, five hundred five".
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