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31212103121100 = 223352113229932537
BaseRepresentation
bin1110001100011001000100…
…10100011011100011001100
311002111211220010120010101000
413012030202110123203030
513042334341344333400
6150214350415420300
76401000004050466
oct706144224334314
9132454803503330
1031212103121100
119a43a84572170
123601146224690
13145539a355a75
1479c961097136
15391d72304600
hex1c632251b8cc

31212103121100 has 288 divisors, whose sum is σ = 109469805984000. Its totient is φ = 7566103641600.

The previous prime is 31212103121081. The next prime is 31212103121113. The reversal of 31212103121100 is 112130121213.

31212103121100 is a `hidden beast` number, since 31 + 2 + 1 + 210 + 312 + 110 + 0 = 666.

It is a super-2 number, since 2×312121031211002 (a number of 28 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 959264032 + ... + 959296568.

It is an arithmetic number, because the mean of its divisors is an integer number (380103493000).

Almost surely, 231212103121100 is an apocalyptic number.

31212103121100 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31212103121100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (54734902992000).

31212103121100 is an abundant number, since it is smaller than the sum of its proper divisors (78257702862900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31212103121100 is a wasteful number, since it uses less digits than its factorization.

31212103121100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64870 (or 64857 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 31212103121100 its reverse (112130121213), we get a palindrome (31324233242313).

The spelling of 31212103121100 in words is "thirty-one trillion, two hundred twelve billion, one hundred three million, one hundred twenty-one thousand, one hundred".