Base | Representation |
---|---|
bin | 100011011110111110110000… |
… | …1011100011011011100101111 |
3 | 1111221010111101022020201000111 |
4 | 1012331331201130123130233 |
5 | 311402243211010210111 |
6 | 3023454300135440451 |
7 | 122513004245003005 |
oct | 10675754134333457 |
9 | 1457114338221014 |
10 | 312121203210031 |
11 | 904a694a2579a6 |
12 | 2b00b21b526127 |
13 | 10520b98358357 |
14 | 5710a65484a75 |
15 | 2613ec71a6a21 |
hex | 11bdf6171b72f |
312121203210031 has 8 divisors (see below), whose sum is σ = 323608966700544. Its totient is φ = 300722148318360.
The previous prime is 312121203210023. The next prime is 312121203210049. The reversal of 312121203210031 is 130012302121213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 312121203210031 - 23 = 312121203210023 is a prime.
It is a super-2 number, since 2×3121212032100312 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 312121203209984 and 312121203210011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312121203210731) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22177142545 + ... + 22177156618.
It is an arithmetic number, because the mean of its divisors is an integer number (40451120837568).
Almost surely, 2312121203210031 is an apocalyptic number.
312121203210031 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
312121203210031 is a deficient number, since it is larger than the sum of its proper divisors (11487763490513).
312121203210031 is a wasteful number, since it uses less digits than its factorization.
312121203210031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44354299421.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 312121203210031 its reverse (130012302121213), we get a palindrome (442133505331244).
The spelling of 312121203210031 in words is "three hundred twelve trillion, one hundred twenty-one billion, two hundred three million, two hundred ten thousand, thirty-one".
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