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31212132002 = 215606066001
BaseRepresentation
bin11101000100011000…
…110101011010100010
32222120020010120212222
4131010120311122202
51002410301211002
622201052151042
72153315513252
oct350430653242
988506116788
1031212132002
1112267486817
126070a68482
132c3554667c
141721415962
15c2a25e1a2
hex7446356a2

31212132002 has 4 divisors (see below), whose sum is σ = 46818198006. Its totient is φ = 15606066000.

The previous prime is 31212132001. The next prime is 31212132019. The reversal of 31212132002 is 20023121213.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 30884196121 + 327935881 = 175739^2 + 18109^2 .

It is a super-2 number, since 2×312121320022 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (31212132001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7803032999 + ... + 7803033002.

Almost surely, 231212132002 is an apocalyptic number.

31212132002 is a deficient number, since it is larger than the sum of its proper divisors (15606066004).

31212132002 is a wasteful number, since it uses less digits than its factorization.

31212132002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15606066003.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 31212132002 its reverse (20023121213), we get a palindrome (51235253215).

It can be divided in two parts, 3121213 and 2002, that multiplied together give a palindrome (6248668426).

The spelling of 31212132002 in words is "thirty-one billion, two hundred twelve million, one hundred thirty-two thousand, two".

Divisors: 1 2 15606066001 31212132002