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312122130000000 = 2735764116231
BaseRepresentation
bin100011011110111111001100…
…0101011110110100010000000
31111221010120202220011111211220
41012331332120223312202000
5311402302110240000000
63023454532124035040
7122513036230410405
oct10675763053664200
91457116686144756
10312122130000000
11904a7285417a21
122b00b439992a80
1310520cb5371898
145710b125b62ac
15261402d7261a0
hex11bdf98af6880

312122130000000 has 512 divisors, whose sum is σ = 1038021061409280. Its totient is φ = 83097600000000.

The previous prime is 312122129999993. The next prime is 312122130000029. The reversal of 312122130000000 is 31221213.

It is a super-3 number, since 3×3121221300000003 (a number of 44 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19229991885 + ... + 19230008115.

It is an arithmetic number, because the mean of its divisors is an integer number (2027384885565).

Almost surely, 2312122130000000 is an apocalyptic number.

312122130000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 312122130000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (519010530704640).

312122130000000 is an abundant number, since it is smaller than the sum of its proper divisors (725898931409280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

312122130000000 is an frugal number, since it uses more digits than its factorization.

312122130000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16924 (or 16882 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 312122130000000 its reverse (31221213), we get a palindrome (312122161221213).

The spelling of 312122130000000 in words is "three hundred twelve trillion, one hundred twenty-two billion, one hundred thirty million", and thus it is an aban number.