Search a number
-
+
31213010013 = 310404336671
BaseRepresentation
bin11101000100011100…
…001011110001011101
32222120021210012021220
4131010130023301131
51002411012310023
622201123043553
72153326131123
oct350434136135
988507705256
1031213010013
1112267a26449
1260712105b9
132c357931c3
1417215a3913
15c2a3843e3
hex74470bc5d

31213010013 has 4 divisors (see below), whose sum is σ = 41617346688. Its totient is φ = 20808673340.

The previous prime is 31213010011. The next prime is 31213010041. The reversal of 31213010013 is 31001031213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31213010013 - 21 = 31213010011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31213009974 and 31213010001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31213010011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5202168333 + ... + 5202168338.

It is an arithmetic number, because the mean of its divisors is an integer number (10404336672).

Almost surely, 231213010013 is an apocalyptic number.

It is an amenable number.

31213010013 is a deficient number, since it is larger than the sum of its proper divisors (10404336675).

31213010013 is a wasteful number, since it uses less digits than its factorization.

31213010013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10404336674.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 31213010013 its reverse (31001031213), we get a palindrome (62214041226).

The spelling of 31213010013 in words is "thirty-one billion, two hundred thirteen million, ten thousand, thirteen".

Divisors: 1 3 10404336671 31213010013