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312130113002 = 2156065056501
BaseRepresentation
bin1001000101011000110…
…01111000110111101010
31002211122212212121120122
410202230121320313222
520103220302104002
6355220211323242
731356606120311
oct4425431706752
91084585777518
10312130113002
11110412347784
12505ab8b0522
1323583c1b476
141117014d278
1581bc5816a2
hex48ac678dea

312130113002 has 4 divisors (see below), whose sum is σ = 468195169506. Its totient is φ = 156065056500.

The previous prime is 312130112999. The next prime is 312130113019. The reversal of 312130113002 is 200311031213.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 257078406841 + 55051706161 = 507029^2 + 234631^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78032528249 + ... + 78032528252.

Almost surely, 2312130113002 is an apocalyptic number.

312130113002 is a deficient number, since it is larger than the sum of its proper divisors (156065056504).

312130113002 is a wasteful number, since it uses less digits than its factorization.

312130113002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156065056503.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 312130113002 its reverse (200311031213), we get a palindrome (512441144215).

The spelling of 312130113002 in words is "three hundred twelve billion, one hundred thirty million, one hundred thirteen thousand, two".

Divisors: 1 2 156065056501 312130113002