Base | Representation |
---|---|
bin | 1001000101011000110… |
… | …01111000110111101010 |
3 | 1002211122212212121120122 |
4 | 10202230121320313222 |
5 | 20103220302104002 |
6 | 355220211323242 |
7 | 31356606120311 |
oct | 4425431706752 |
9 | 1084585777518 |
10 | 312130113002 |
11 | 110412347784 |
12 | 505ab8b0522 |
13 | 23583c1b476 |
14 | 1117014d278 |
15 | 81bc5816a2 |
hex | 48ac678dea |
312130113002 has 4 divisors (see below), whose sum is σ = 468195169506. Its totient is φ = 156065056500.
The previous prime is 312130112999. The next prime is 312130113019. The reversal of 312130113002 is 200311031213.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 257078406841 + 55051706161 = 507029^2 + 234631^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78032528249 + ... + 78032528252.
Almost surely, 2312130113002 is an apocalyptic number.
312130113002 is a deficient number, since it is larger than the sum of its proper divisors (156065056504).
312130113002 is a wasteful number, since it uses less digits than its factorization.
312130113002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156065056503.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 312130113002 its reverse (200311031213), we get a palindrome (512441144215).
The spelling of 312130113002 in words is "three hundred twelve billion, one hundred thirty million, one hundred thirteen thousand, two".
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