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31213021113000 = 23335310131736107
BaseRepresentation
bin1110001100011010110010…
…00010010010101010101000
311002111221021002220221112000
413012031121002102222220
513042343231401104000
6150215021451251000
76401031521622636
oct706153102225250
9132457232827460
1031213021113000
119a44405773061
123601361749a60
1314554b55ab83c
1479ca0ad78356
15391dc7bd7000
hex1c6359092aa8

31213021113000 has 512 divisors, whose sum is σ = 109624234636800. Its totient is φ = 8214837120000.

The previous prime is 31213021112963. The next prime is 31213021113049. The reversal of 31213021113000 is 31112031213.

31213021113000 is a `hidden beast` number, since 3 + 121 + 30 + 211 + 1 + 300 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 864440947 + ... + 864477053.

It is an arithmetic number, because the mean of its divisors is an integer number (214109833275).

Almost surely, 231213021113000 is an apocalyptic number.

31213021113000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31213021113000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (54812117318400).

31213021113000 is an abundant number, since it is smaller than the sum of its proper divisors (78411213523800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31213021113000 is a wasteful number, since it uses less digits than its factorization.

31213021113000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36555 (or 36535 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 31213021113000 its reverse (31112031213), we get a palindrome (31244133144213).

The spelling of 31213021113000 in words is "thirty-one trillion, two hundred thirteen billion, twenty-one million, one hundred thirteen thousand".