Base | Representation |
---|---|
bin | 11101000100011101… |
… | …101111111001100101 |
3 | 2222120022120000212112 |
4 | 131010131233321211 |
5 | 1002411113421013 |
6 | 22201135530405 |
7 | 2153332456610 |
oct | 350435577145 |
9 | 88508500775 |
10 | 31213420133 |
11 | 12268186595 |
12 | 6071389a05 |
13 | 2c358a7a8c |
14 | 172166d177 |
15 | c2a415ba8 |
hex | 74476fe65 |
31213420133 has 8 divisors (see below), whose sum is σ = 35713162752. Its totient is φ = 26723848176.
The previous prime is 31213420127. The next prime is 31213420169. The reversal of 31213420133 is 33102431213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31213420133 - 232 = 26918452837 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31213420099 and 31213420108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31213422133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2536085 + ... + 2548362.
It is an arithmetic number, because the mean of its divisors is an integer number (4464145344).
Almost surely, 231213420133 is an apocalyptic number.
It is an amenable number.
31213420133 is a deficient number, since it is larger than the sum of its proper divisors (4499742619).
31213420133 is an equidigital number, since it uses as much as digits as its factorization.
31213420133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5085331.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 31213420133 its reverse (33102431213), we get a palindrome (64315851346).
The spelling of 31213420133 in words is "thirty-one billion, two hundred thirteen million, four hundred twenty thousand, one hundred thirty-three".
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