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312140113 = 1947431811
BaseRepresentation
bin10010100110101…
…110000101010001
3210202100100201221
4102212232011101
51114401440423
650550125041
710510101325
oct2246560521
9722310657
10312140113
1115021653a
1288650781
134c88b7bc
142d653985
151c60ae5d
hex129ae151

312140113 has 16 divisors (see below), whose sum is σ = 336752640. Its totient is φ = 288392400.

The previous prime is 312140063. The next prime is 312140117. The reversal of 312140113 is 311041213.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-312140113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312140117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 384478 + ... + 385288.

It is an arithmetic number, because the mean of its divisors is an integer number (21047040).

Almost surely, 2312140113 is an apocalyptic number.

It is an amenable number.

312140113 is a deficient number, since it is larger than the sum of its proper divisors (24612527).

312140113 is a wasteful number, since it uses less digits than its factorization.

312140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1308.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 312140113 is about 17667.4874557759. The cubic root of 312140113 is about 678.3438017865.

Adding to 312140113 its reverse (311041213), we get a palindrome (623181326).

It can be divided in two parts, 3121 and 40113, that added together give a palindrome (43234).

The spelling of 312140113 in words is "three hundred twelve million, one hundred forty thousand, one hundred thirteen".

Divisors: 1 19 47 431 811 893 8189 15409 20257 38117 349541 384883 724223 6641279 16428427 312140113