Base | Representation |
---|---|
bin | 1110001100011100110101… |
… | …00011111001010111101011 |
3 | 11002112001002201111121110211 |
4 | 13012032122203321113223 |
5 | 13042403004313110243 |
6 | 150215322521521551 |
7 | 6401101001020531 |
oct | 706163243712753 |
9 | 132461081447424 |
10 | 31214120441323 |
11 | 9a4491a269766 |
12 | 36016099432b7 |
13 | 145562c285881 |
14 | 79cab2d80151 |
15 | 391e3e488d9d |
hex | 1c639a8f95eb |
31214120441323 has 4 divisors (see below), whose sum is σ = 31214300420800. Its totient is φ = 31213940461848.
The previous prime is 31214120441281. The next prime is 31214120441327. The reversal of 31214120441323 is 32314402141213.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31214120441323 - 225 = 31214086886891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31214120441327) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89729340 + ... + 90076537.
It is an arithmetic number, because the mean of its divisors is an integer number (7803575105200).
Almost surely, 231214120441323 is an apocalyptic number.
31214120441323 is a deficient number, since it is larger than the sum of its proper divisors (179979477).
31214120441323 is a wasteful number, since it uses less digits than its factorization.
31214120441323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179979476.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 31214120441323 its reverse (32314402141213), we get a palindrome (63528522582536).
The spelling of 31214120441323 in words is "thirty-one trillion, two hundred fourteen billion, one hundred twenty million, four hundred forty-one thousand, three hundred twenty-three".
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