Base | Representation |
---|---|
bin | 101101011011000010110… |
… | …101110100011111011111 |
3 | 102001101220210021201112121 |
4 | 231123002311310133133 |
5 | 402120124234123224 |
6 | 10345542555243411 |
7 | 441341401651663 |
oct | 55330265643737 |
9 | 12041823251477 |
10 | 3121415145439 |
11 | aa386a524588 |
12 | 424b4b749567 |
13 | 19846ac69626 |
14 | ab1121748a3 |
15 | 562dda81be4 |
hex | 2d6c2d747df |
3121415145439 has 4 divisors (see below), whose sum is σ = 3121455510160. Its totient is φ = 3121374780720.
The previous prime is 3121415145383. The next prime is 3121415145449. The reversal of 3121415145439 is 9345415141213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3121415145439 - 215 = 3121415112671 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3121415145395 and 3121415145404.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3121415145449) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20066142 + ... + 20221099.
It is an arithmetic number, because the mean of its divisors is an integer number (780363877540).
Almost surely, 23121415145439 is an apocalyptic number.
3121415145439 is a deficient number, since it is larger than the sum of its proper divisors (40364721).
3121415145439 is an equidigital number, since it uses as much as digits as its factorization.
3121415145439 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40364720.
The product of its digits is 259200, while the sum is 43.
The spelling of 3121415145439 in words is "three trillion, one hundred twenty-one billion, four hundred fifteen million, one hundred forty-five thousand, four hundred thirty-nine".
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