Base | Representation |
---|---|
bin | 100011011111001000100000… |
… | …1000001100101110101010011 |
3 | 1111221012111102000111010102222 |
4 | 1012332101001001211311103 |
5 | 311403114042314441433 |
6 | 3023512041122131255 |
7 | 122514345032660111 |
oct | 10676210101456523 |
9 | 1457174360433388 |
10 | 312142134140243 |
11 | 90504810214630 |
12 | 2b0132a11b0b2b |
13 | 10522b52868b64 |
14 | 5711a8d258ab1 |
15 | 26147eea0db98 |
hex | 11be441065d53 |
312142134140243 has 8 divisors (see below), whose sum is σ = 340987080645120. Its totient is φ = 283375252444680.
The previous prime is 312142134140237. The next prime is 312142134140279. The reversal of 312142134140243 is 342041431241213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 312142134140243 - 222 = 312142129945939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (312142134146243) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19516193963 + ... + 19516209956.
It is an arithmetic number, because the mean of its divisors is an integer number (42623385080640).
Almost surely, 2312142134140243 is an apocalyptic number.
312142134140243 is a deficient number, since it is larger than the sum of its proper divisors (28844946504877).
312142134140243 is a wasteful number, since it uses less digits than its factorization.
312142134140243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39032404657.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 312142134140243 its reverse (342041431241213), we get a palindrome (654183565381456).
The spelling of 312142134140243 in words is "three hundred twelve trillion, one hundred forty-two billion, one hundred thirty-four million, one hundred forty thousand, two hundred forty-three".
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