Base | Representation |
---|---|
bin | 100011011111001000100000… |
… | …1000001100111010011000011 |
3 | 1111221012111102000111102200012 |
4 | 1012332101001001213103003 |
5 | 311403114042320134433 |
6 | 3023512041122215135 |
7 | 122514345033013442 |
oct | 10676210101472303 |
9 | 1457174360442605 |
10 | 312142134146243 |
11 | 90504810219095 |
12 | 2b0132a11b44ab |
13 | 10522b5286b7cb |
14 | 5711a8d25ad59 |
15 | 26147eea10848 |
hex | 11be4410674c3 |
312142134146243 has 2 divisors, whose sum is σ = 312142134146244. Its totient is φ = 312142134146242.
The previous prime is 312142134146201. The next prime is 312142134146287. The reversal of 312142134146243 is 342641431241213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312142134146243 - 238 = 311867256239299 is a prime.
It is a super-2 number, since 2×3121421341462432 (a number of 30 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 312142134146243.
It is not a weakly prime, because it can be changed into another prime (312142134146443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156071067073121 + 156071067073122.
It is an arithmetic number, because the mean of its divisors is an integer number (156071067073122).
Almost surely, 2312142134146243 is an apocalyptic number.
312142134146243 is a deficient number, since it is larger than the sum of its proper divisors (1).
312142134146243 is an equidigital number, since it uses as much as digits as its factorization.
312142134146243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 331776, while the sum is 41.
Adding to 312142134146243 its reverse (342641431241213), we get a palindrome (654783565387456).
The spelling of 312142134146243 in words is "three hundred twelve trillion, one hundred forty-two billion, one hundred thirty-four million, one hundred forty-six thousand, two hundred forty-three".
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