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312153120434 = 2156076560217
BaseRepresentation
bin1001000101011011100…
…01101001111010110010
31002211201111011111211202
410202231301221322302
520103242144323214
6355222352411202
731360305513341
oct4425561517262
91084644144752
10312153120434
11110424331591
12505b7546b02
132358891572c
141117321bb58
1581be5c86de
hex48adc69eb2

312153120434 has 4 divisors (see below), whose sum is σ = 468229680654. Its totient is φ = 156076560216.

The previous prime is 312153120431. The next prime is 312153120449. The reversal of 312153120434 is 434021351213.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 434021351213 = 2318870493531.

It can be written as a sum of positive squares in only one way, i.e., 311304854809 + 848265625 = 557947^2 + 29125^2 .

It is a junction number, because it is equal to n+sod(n) for n = 312153120397 and 312153120406.

It is not an unprimeable number, because it can be changed into a prime (312153120431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78038280107 + ... + 78038280110.

Almost surely, 2312153120434 is an apocalyptic number.

312153120434 is a deficient number, since it is larger than the sum of its proper divisors (156076560220).

312153120434 is a wasteful number, since it uses less digits than its factorization.

312153120434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156076560219.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 312153120434 its reverse (434021351213), we get a palindrome (746174471647).

The spelling of 312153120434 in words is "three hundred twelve billion, one hundred fifty-three million, one hundred twenty thousand, four hundred thirty-four".

Divisors: 1 2 156076560217 312153120434