Base | Representation |
---|---|
bin | 100011011111101001100001… |
… | …1010110110010010111001001 |
3 | 1111221110021102120202202021121 |
4 | 1012333103003112302113021 |
5 | 311410244301243231101 |
6 | 3024004405101235241 |
7 | 122522435121432460 |
oct | 10677230326622711 |
9 | 1457407376682247 |
10 | 312213040211401 |
11 | 9053189690533a |
12 | 2b024b8b562b21 |
13 | 10529742924394 |
14 | 571529832b9d7 |
15 | 261659e94a0a1 |
hex | 11bf4c35b25c9 |
312213040211401 has 8 divisors (see below), whose sum is σ = 356873101631424. Its totient is φ = 267567528424560.
The previous prime is 312213040211341. The next prime is 312213040211419. The reversal of 312213040211401 is 104112040312213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 312213040211401 - 213 = 312213040203209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (312213040211431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3637362310 + ... + 3637448143.
It is an arithmetic number, because the mean of its divisors is an integer number (44609137703928).
Almost surely, 2312213040211401 is an apocalyptic number.
It is an amenable number.
312213040211401 is a deficient number, since it is larger than the sum of its proper divisors (44660061420023).
312213040211401 is an equidigital number, since it uses as much as digits as its factorization.
312213040211401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7274816591.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 312213040211401 its reverse (104112040312213), we get a palindrome (416325080523614).
The spelling of 312213040211401 in words is "three hundred twelve trillion, two hundred thirteen billion, forty million, two hundred eleven thousand, four hundred one".
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