Base | Representation |
---|---|
bin | 100011011111101110001110… |
… | …1011000100001011001101111 |
3 | 1111221111020111111100010102211 |
4 | 1012333130131120201121233 |
5 | 311410430442440102010 |
6 | 3024013155230431251 |
7 | 122523243325050514 |
oct | 10677343530413157 |
9 | 1457436444303384 |
10 | 312223140550255 |
11 | 905360aa222420 |
12 | 2b026b2a062527 |
13 | 1052a69234364c |
14 | 571597592d30b |
15 | 261699152808a |
hex | 11bf71d62166f |
312223140550255 has 128 divisors (see below), whose sum is σ = 429376315530240. Its totient is φ = 215926177628160.
The previous prime is 312223140550249. The next prime is 312223140550261. The reversal of 312223140550255 is 552055041322213.
It is an interprime number because it is at equal distance from previous prime (312223140550249) and next prime (312223140550261).
It is a de Polignac number, because none of the positive numbers 2k-312223140550255 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 47573231604 + ... + 47573238166.
It is an arithmetic number, because the mean of its divisors is an integer number (3354502465080).
Almost surely, 2312223140550255 is an apocalyptic number.
312223140550255 is a deficient number, since it is larger than the sum of its proper divisors (117153174979985).
312223140550255 is a wasteful number, since it uses less digits than its factorization.
312223140550255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8921.
The product of its (nonzero) digits is 360000, while the sum is 40.
Adding to 312223140550255 its reverse (552055041322213), we get a palindrome (864278181872468).
The spelling of 312223140550255 in words is "three hundred twelve trillion, two hundred twenty-three billion, one hundred forty million, five hundred fifty thousand, two hundred fifty-five".
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