Base | Representation |
---|---|
bin | 1110001100111010100110… |
… | …00001111000010100111001 |
3 | 11002120120100101021000111020 |
4 | 13012131103001320110321 |
5 | 13043133221123223001 |
6 | 150230524315453053 |
7 | 6402204665562366 |
oct | 706352301702471 |
9 | 132516311230436 |
10 | 31230100211001 |
11 | 9a5067a44718a |
12 | 3604729457189 |
13 | 1456ca7aa78a3 |
14 | 79d78b36746d |
15 | 3925772d5736 |
hex | 1c6753078539 |
31230100211001 has 16 divisors (see below), whose sum is σ = 41662393977600. Its totient is φ = 20808939489408.
The previous prime is 31230100210993. The next prime is 31230100211021. The reversal of 31230100211001 is 10011200103213.
It is a happy number.
It is not a de Polignac number, because 31230100211001 - 23 = 31230100210993 is a prime.
It is a super-4 number, since 4×312301002110014 (a number of 55 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (31230100211021) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43753360 + ... + 44461406.
It is an arithmetic number, because the mean of its divisors is an integer number (2603899623600).
Almost surely, 231230100211001 is an apocalyptic number.
It is an amenable number.
31230100211001 is a deficient number, since it is larger than the sum of its proper divisors (10432293766599).
31230100211001 is a wasteful number, since it uses less digits than its factorization.
31230100211001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 715888.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 31230100211001 its reverse (10011200103213), we get a palindrome (41241300314214).
The spelling of 31230100211001 in words is "thirty-one trillion, two hundred thirty billion, one hundred million, two hundred eleven thousand, one".
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