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31231113000000 = 2635694710993
BaseRepresentation
bin1110001100111100011110…
…11001010111010001000000
311002120122221222000000210220
413012132033121113101000
513043142304412000000
6150231213015223040
76402242044260114
oct706361731272100
9132518858000726
1031231113000000
119a5104a105591
123604970677a80
131457109871c14
1479d845a83744
153925d61911a0
hex1c678f657440

31231113000000 has 392 divisors, whose sum is σ = 103407553241376. Its totient is φ = 8318745600000.

The previous prime is 31231112999981. The next prime is 31231113000089. The reversal of 31231113000000 is 31113213.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 2840994504 + ... + 2841005496.

Almost surely, 231231113000000 is an apocalyptic number.

31231113000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31231113000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (51703776620688).

31231113000000 is an abundant number, since it is smaller than the sum of its proper divisors (72176440241376).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31231113000000 is an frugal number, since it uses more digits than its factorization.

31231113000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11985 (or 11950 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 31231113000000 its reverse (31113213), we get a palindrome (31231144113213).

The spelling of 31231113000000 in words is "thirty-one trillion, two hundred thirty-one billion, one hundred thirteen million", and thus it is an aban number.