Base | Representation |
---|---|
bin | 1110001100111110010110… |
… | …00100110011011100010001 |
3 | 11002120202112202000110110202 |
4 | 13012133023010303130101 |
5 | 13043201332221241340 |
6 | 150231500223304545 |
7 | 6402305622556661 |
oct | 706371304633421 |
9 | 132522482013422 |
10 | 31232114243345 |
11 | 9a515132a8524 |
12 | 3604baba4b155 |
13 | 1457239125cc2 |
14 | 79d8dca361a1 |
15 | 39264401ac15 |
hex | 1c67cb133711 |
31232114243345 has 16 divisors (see below), whose sum is σ = 39823380120960. Its totient is φ = 23432849612544.
The previous prime is 31232114243339. The next prime is 31232114243389. The reversal of 31232114243345 is 54334241123213.
It is a cyclic number.
It is not a de Polignac number, because 31232114243345 - 210 = 31232114242321 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31232114243299 and 31232114243308.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 649157285 + ... + 649205394.
It is an arithmetic number, because the mean of its divisors is an integer number (2488961257560).
Almost surely, 231232114243345 is an apocalyptic number.
It is an amenable number.
31232114243345 is a deficient number, since it is larger than the sum of its proper divisors (8591265877615).
31232114243345 is a wasteful number, since it uses less digits than its factorization.
31232114243345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1298362984.
The product of its digits is 207360, while the sum is 38.
Adding to 31232114243345 its reverse (54334241123213), we get a palindrome (85566355366558).
The spelling of 31232114243345 in words is "thirty-one trillion, two hundred thirty-two billion, one hundred fourteen million, two hundred forty-three thousand, three hundred forty-five".
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