Base | Representation |
---|---|
bin | 101101011101011100111… |
… | …011100001100101000111 |
3 | 102001122120221202210221211 |
4 | 231131130323201211013 |
5 | 402140423041111403 |
6 | 10351051304552251 |
7 | 441462432455230 |
oct | 55353473414507 |
9 | 12048527683854 |
10 | 3124000332103 |
11 | aa4976821592 |
12 | 425551482687 |
13 | 198790723b91 |
14 | ab2b963c087 |
15 | 563e09d806d |
hex | 2d75cee1947 |
3124000332103 has 16 divisors (see below), whose sum is σ = 3620081298240. Its totient is φ = 2640529495296.
The previous prime is 3124000332073. The next prime is 3124000332121. The reversal of 3124000332103 is 3012330004213.
It is not a de Polignac number, because 3124000332103 - 213 = 3124000323911 is a prime.
It is a super-3 number, since 3×31240003321033 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3124000032103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6489400 + ... + 6954157.
It is an arithmetic number, because the mean of its divisors is an integer number (226255081140).
Almost surely, 23124000332103 is an apocalyptic number.
3124000332103 is a deficient number, since it is larger than the sum of its proper divisors (496080966137).
3124000332103 is a wasteful number, since it uses less digits than its factorization.
3124000332103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13444026.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 3124000332103 its reverse (3012330004213), we get a palindrome (6136330336316).
The spelling of 3124000332103 in words is "three trillion, one hundred twenty-four billion, three hundred thirty-two thousand, one hundred three".
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