Base | Representation |
---|---|
bin | 101101011101100100001… |
… | …001110000100110011001 |
3 | 102001122220101202222202112 |
4 | 231131210021300212121 |
5 | 402141200101113103 |
6 | 10351111314042105 |
7 | 441465433430426 |
oct | 55354411604631 |
9 | 12048811688675 |
10 | 3124121504153 |
11 | aa4a29163981 |
12 | 425585b79335 |
13 | 1987ac86b410 |
14 | ab2cb780d4d |
15 | 563eb470cd8 |
hex | 2d764270999 |
3124121504153 has 16 divisors (see below), whose sum is σ = 3541621406400. Its totient is φ = 2731942624320.
The previous prime is 3124121504149. The next prime is 3124121504243. The reversal of 3124121504153 is 3514051214213.
It is not a de Polignac number, because 3124121504153 - 22 = 3124121504149 is a prime.
It is a super-2 number, since 2×31241215041532 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3124121504143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8852558 + ... + 9198696.
It is an arithmetic number, because the mean of its divisors is an integer number (221351337900).
Almost surely, 23124121504153 is an apocalyptic number.
It is an amenable number.
3124121504153 is a deficient number, since it is larger than the sum of its proper divisors (417499902247).
3124121504153 is a wasteful number, since it uses less digits than its factorization.
3124121504153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 382712.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 3124121504153 its reverse (3514051214213), we get a palindrome (6638172718366).
The spelling of 3124121504153 in words is "three trillion, one hundred twenty-four billion, one hundred twenty-one million, five hundred four thousand, one hundred fifty-three".
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