Base | Representation |
---|---|
bin | 100011100001001011010111… |
… | …0100001010011011000001100 |
3 | 1111222012100202002012022111211 |
4 | 1013002112232201103120030 |
5 | 311422220044333402134 |
6 | 3024245113323424204 |
7 | 122543553520515505 |
oct | 10702265641233014 |
9 | 1458170662168454 |
10 | 312423144044044 |
11 | 90602a02a5a550 |
12 | 2b059846985064 |
13 | 105434b72b6b47 |
14 | 572150a27dbac |
15 | 261bc99e3c764 |
hex | 11c25ae85360c |
312423144044044 has 48 divisors (see below), whose sum is σ = 597019776716160. Its totient is φ = 141873512696960.
The previous prime is 312423144044027. The next prime is 312423144044101. The reversal of 312423144044044 is 440440441324213.
It is a super-2 number, since 2×3124231440440442 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 312423144043988 and 312423144044006.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 326192019 + ... + 327148405.
It is an arithmetic number, because the mean of its divisors is an integer number (12437912014920).
Almost surely, 2312423144044044 is an apocalyptic number.
It is an amenable number.
312423144044044 is a deficient number, since it is larger than the sum of its proper divisors (284596632672116).
312423144044044 is a wasteful number, since it uses less digits than its factorization.
312423144044044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 963558 (or 963556 counting only the distinct ones).
The product of its (nonzero) digits is 589824, while the sum is 40.
Adding to 312423144044044 its reverse (440440441324213), we get a palindrome (752863585368257).
The spelling of 312423144044044 in words is "three hundred twelve trillion, four hundred twenty-three billion, one hundred forty-four million, forty-four thousand, forty-four".
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