312425413331541 has 4 divisors (see below), whose sum is σ = 416567217775392. Its totient is φ = 208283608887692.

The previous prime is 312425413331503. The next prime is 312425413331561. The reversal of 312425413331541 is 145133314524213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 312425413331541 - 2⁹ = 312425413331029 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 312425413331493 and 312425413331502.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312425413331561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52070902221921 + ... + 52070902221926.

It is an arithmetic number, because the mean of its divisors is an integer number (104141804443848).

Almost surely, 2^{312425413331541} is an apocalyptic number.

It is an amenable number.

312425413331541 is a deficient number, since it is larger than the sum of its proper divisors (104141804443851).

312425413331541 is a wasteful number, since it uses less digits than its factorization.

312425413331541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104141804443850.

The product of its digits is 518400, while the sum is 42.

Adding to 312425413331541 its reverse (145133314524213), we get a palindrome (457558727855754).

The spelling of 312425413331541 in words is "three hundred twelve trillion, four hundred twenty-five billion, four hundred thirteen million, three hundred thirty-one thousand, five hundred forty-one".