Base | Representation |
---|---|
bin | 1110001101010011000101… |
… | …10110000000010101001101 |
3 | 11002121211021211201122002112 |
4 | 13012221202312000111031 |
5 | 13043342134102413110 |
6 | 150240541234433405 |
7 | 6403151604623141 |
oct | 706514266002515 |
9 | 132554254648075 |
10 | 31243250435405 |
11 | 9a562083a7438 |
12 | 3607199432865 |
13 | 14582c2326668 |
14 | 7a0277a39221 |
15 | 392a96a0d405 |
hex | 1c6a62d8054d |
31243250435405 has 16 divisors (see below), whose sum is σ = 37503082041984. Its totient is φ = 24987147165120.
The previous prime is 31243250435377. The next prime is 31243250435477. The reversal of 31243250435405 is 50453405234213.
It is not a de Polignac number, because 31243250435405 - 216 = 31243250369869 is a prime.
It is a super-2 number, since 2×312432504354052 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 237361160 + ... + 237492750.
It is an arithmetic number, because the mean of its divisors is an integer number (2343942627624).
Almost surely, 231243250435405 is an apocalyptic number.
It is an amenable number.
31243250435405 is a deficient number, since it is larger than the sum of its proper divisors (6259831606579).
31243250435405 is a wasteful number, since it uses less digits than its factorization.
31243250435405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145396.
The product of its (nonzero) digits is 864000, while the sum is 41.
Adding to 31243250435405 its reverse (50453405234213), we get a palindrome (81696655669618).
The spelling of 31243250435405 in words is "thirty-one trillion, two hundred forty-three billion, two hundred fifty million, four hundred thirty-five thousand, four hundred five".
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