Base | Representation |
---|---|
bin | 1001000101111100111… |
… | …01011101111010011111 |
3 | 1002212102222212221202011 |
4 | 10202332131131322133 |
5 | 20104330324303210 |
6 | 355310232212051 |
7 | 31400245013422 |
oct | 4427635357237 |
9 | 1085388787664 |
10 | 312433041055 |
11 | 110558341043 |
12 | 5067523a027 |
13 | 23601902c35 |
14 | 1119c4859b9 |
15 | 81d8e6cd8a |
hex | 48be75de9f |
312433041055 has 4 divisors (see below), whose sum is σ = 374919649272. Its totient is φ = 249946432840.
The previous prime is 312433041047. The next prime is 312433041091. The reversal of 312433041055 is 550140334213.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 312433041055 - 23 = 312433041047 is a prime.
It is a super-2 number, since 2×3124330410552 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31243304101 + ... + 31243304110.
It is an arithmetic number, because the mean of its divisors is an integer number (93729912318).
Almost surely, 2312433041055 is an apocalyptic number.
312433041055 is a deficient number, since it is larger than the sum of its proper divisors (62486608217).
312433041055 is an equidigital number, since it uses as much as digits as its factorization.
312433041055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62486608216.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 312433041055 its reverse (550140334213), we get a palindrome (862573375268).
The spelling of 312433041055 in words is "three hundred twelve billion, four hundred thirty-three million, forty-one thousand, fifty-five".
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