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312433130441 = 337091926851
BaseRepresentation
bin1001000101111100111…
…01110011101111001001
31002212110000001111100202
410202332131303233021
520104330340133231
6355310234141545
731400245535135
oct4427635635711
91085400044322
10312433130441
111105583a2213
12506752818b5
1323601934823
141119c4aa3c5
1581d8e895cb
hex48be773bc9

312433130441 has 4 divisors (see below), whose sum is σ = 312434394384. Its totient is φ = 312431866500.

The previous prime is 312433130437. The next prime is 312433130453. The reversal of 312433130441 is 144031334213.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 144031334213 = 1311079333401.

It is a cyclic number.

It is not a de Polignac number, because 312433130441 - 22 = 312433130437 is a prime.

It is a super-2 number, since 2×3124331304412 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312433130461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126335 + ... + 800516.

It is an arithmetic number, because the mean of its divisors is an integer number (78108598596).

Almost surely, 2312433130441 is an apocalyptic number.

It is an amenable number.

312433130441 is a deficient number, since it is larger than the sum of its proper divisors (1263943).

312433130441 is an equidigital number, since it uses as much as digits as its factorization.

312433130441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1263942.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 312433130441 its reverse (144031334213), we get a palindrome (456464464654).

The spelling of 312433130441 in words is "three hundred twelve billion, four hundred thirty-three million, one hundred thirty thousand, four hundred forty-one".

Divisors: 1 337091 926851 312433130441