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31255242433 = 155069201557
BaseRepresentation
bin11101000110111101…
…010010011011000001
32222200020020211021121
4131012331102123001
51003002320224213
622205232152241
72154351114532
oct350675223301
988606224247
1031255242433
1112289851278
126083398681
132c4145bbbc
141727038689
15c2de2788d
hex746f526c1

31255242433 has 4 divisors (see below), whose sum is σ = 31255599060. Its totient is φ = 31254885808.

The previous prime is 31255242419. The next prime is 31255242439. The reversal of 31255242433 is 33424255213.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 20836345104 + 10418897329 = 144348^2 + 102073^2 .

It is a cyclic number.

It is not a de Polignac number, because 31255242433 - 29 = 31255241921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31255242439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54291 + ... + 255847.

It is an arithmetic number, because the mean of its divisors is an integer number (7813899765).

Almost surely, 231255242433 is an apocalyptic number.

It is an amenable number.

31255242433 is a deficient number, since it is larger than the sum of its proper divisors (356627).

31255242433 is a wasteful number, since it uses less digits than its factorization.

31255242433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 356626.

The product of its digits is 86400, while the sum is 34.

Adding to 31255242433 its reverse (33424255213), we get a palindrome (64679497646).

The spelling of 31255242433 in words is "thirty-one billion, two hundred fifty-five million, two hundred forty-two thousand, four hundred thirty-three".

Divisors: 1 155069 201557 31255242433