Base | Representation |
---|---|
bin | 1011101001010101… |
… | …0000101001101011 |
3 | 22001212101010120201 |
4 | 2322111100221223 |
5 | 22400242313103 |
6 | 1234111533031 |
7 | 140316466246 |
oct | 27225205153 |
9 | 8055333521 |
10 | 3126135403 |
11 | 1364692886 |
12 | 732b2a177 |
13 | 3aa878c81 |
14 | 21927c25d |
15 | 1346ac51d |
hex | ba550a6b |
3126135403 has 4 divisors (see below), whose sum is σ = 3126950608. Its totient is φ = 3125320200.
The previous prime is 3126135401. The next prime is 3126135451. The reversal of 3126135403 is 3045316213.
3126135403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3045316213 = 113 ⋅26949701.
It is a cyclic number.
It is not a de Polignac number, because 3126135403 - 21 = 3126135401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3126135401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 401823 + ... + 409528.
It is an arithmetic number, because the mean of its divisors is an integer number (781737652).
Almost surely, 23126135403 is an apocalyptic number.
3126135403 is a deficient number, since it is larger than the sum of its proper divisors (815205).
3126135403 is an equidigital number, since it uses as much as digits as its factorization.
3126135403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 815204.
The product of its (nonzero) digits is 6480, while the sum is 28.
The square root of 3126135403 is about 55911.8538683882. The cubic root of 3126135403 is about 1462.1859110540.
The spelling of 3126135403 in words is "three billion, one hundred twenty-six million, one hundred thirty-five thousand, four hundred three".
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