Base | Representation |
---|---|
bin | 101101100001100111101… |
… | …001000001110011100011 |
3 | 102002002010210122111101202 |
4 | 231201213221001303203 |
5 | 402224104100000120 |
6 | 10353111312351415 |
7 | 442011345511310 |
oct | 55414751016343 |
9 | 12062123574352 |
10 | 3128475000035 |
11 | aa686263a860 |
12 | 42639bb4556b |
13 | 19902479b298 |
14 | ab5c1a31d07 |
15 | 565a3770875 |
hex | 2d867a41ce3 |
3128475000035 has 16 divisors (see below), whose sum is σ = 4680523636992. Its totient is φ = 1950218181600.
The previous prime is 3128475000029. The next prime is 3128475000103. The reversal of 3128475000035 is 5300005748213.
3128475000035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3128475000035 - 210 = 3128474999011 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4062954161 + ... + 4062954930.
It is an arithmetic number, because the mean of its divisors is an integer number (292532727312).
Almost surely, 23128475000035 is an apocalyptic number.
3128475000035 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
3128475000035 is a deficient number, since it is larger than the sum of its proper divisors (1552048636957).
3128475000035 is a wasteful number, since it uses less digits than its factorization.
3128475000035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8125909114.
The product of its (nonzero) digits is 100800, while the sum is 38.
The spelling of 3128475000035 in words is "three trillion, one hundred twenty-eight billion, four hundred seventy-five million, thirty-five", and thus it is an aban number.
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