Base | Representation |
---|---|
bin | 101101100011000100010… |
… | …101011001001011110011 |
3 | 102002020011011220111011010 |
4 | 231203010111121023303 |
5 | 402240300203242003 |
6 | 10353525504322003 |
7 | 442065031105503 |
oct | 55430425311363 |
9 | 12066134814133 |
10 | 3130030134003 |
11 | aa7490457a43 |
12 | 426754913303 |
13 | 199211a256b6 |
14 | ab6cc3a7a03 |
15 | 5664505b003 |
hex | 2d8c45592f3 |
3130030134003 has 4 divisors (see below), whose sum is σ = 4173373512008. Its totient is φ = 2086686756000.
The previous prime is 3130030133983. The next prime is 3130030134043. The reversal of 3130030134003 is 3004310300313.
3130030134003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 3130030134003 - 214 = 3130030117619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3130030134043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 521671688998 + ... + 521671689003.
It is an arithmetic number, because the mean of its divisors is an integer number (1043343378002).
Almost surely, 23130030134003 is an apocalyptic number.
3130030134003 is a deficient number, since it is larger than the sum of its proper divisors (1043343378005).
3130030134003 is a wasteful number, since it uses less digits than its factorization.
3130030134003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1043343378004.
The product of its (nonzero) digits is 972, while the sum is 21.
Adding to 3130030134003 its reverse (3004310300313), we get a palindrome (6134340434316).
The spelling of 3130030134003 in words is "three trillion, one hundred thirty billion, thirty million, one hundred thirty-four thousand, three".
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