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31300401412135 = 56260080282427
BaseRepresentation
bin1110001110111101100010…
…10011101011100000100111
311002211021210210101001122101
413013132301103223200213
513100311210230142020
6150323112250312531
76410244061123432
oct707366123534047
9132737723331571
1031300401412135
119a78475663109
123616289128747
1314607cc75095b
147a2d39d86819
153942de09100a
hex1c77b14eb827

31300401412135 has 4 divisors (see below), whose sum is σ = 37560481694568. Its totient is φ = 25040321129704.

The previous prime is 31300401412121. The next prime is 31300401412157. The reversal of 31300401412135 is 53121410400313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31300401412135 - 25 = 31300401412103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3130040141209 + ... + 3130040141218.

It is an arithmetic number, because the mean of its divisors is an integer number (9390120423642).

Almost surely, 231300401412135 is an apocalyptic number.

31300401412135 is a deficient number, since it is larger than the sum of its proper divisors (6260080282433).

31300401412135 is an equidigital number, since it uses as much as digits as its factorization.

31300401412135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6260080282432.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 31300401412135 its reverse (53121410400313), we get a palindrome (84421811812448).

The spelling of 31300401412135 in words is "thirty-one trillion, three hundred billion, four hundred one million, four hundred twelve thousand, one hundred thirty-five".

Divisors: 1 5 6260080282427 31300401412135