3130254041 has 4 divisors (see below), whose sum is σ = 3189315492. Its totient is φ = 3071192592.

The previous prime is 3130254037. The next prime is 3130254053. The reversal of 3130254041 is 1404520313.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2784145225 + 346108816 = 52765^2 + 18604^2 .

It is a cyclic number.

It is not a de Polignac number, because 3130254041 - 2² = 3130254037 is a prime.

It is a super-2 number, since 2×3130254041² = 19596980722393659362, which contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3130253998 and 3130254016.

It is not an unprimeable number, because it can be changed into a prime (3130254011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29530646 + ... + 29530751.

It is an arithmetic number, because the mean of its divisors is an integer number (797328873).

Almost surely, 2^3130254041 is an apocalyptic number.

It is an amenable number.

3130254041 is a deficient number, since it is larger than the sum of its proper divisors (59061451).

3130254041 is an equidigital number, since it uses as much as digits as its factorization.

3130254041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59061450.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 3130254041 is about 55948.6732729204. The cubic root of 3130254041 is about 1462.8277654938.

Adding to 3130254041 its reverse (1404520313), we get a palindrome (4534774354).

The spelling of 3130254041 in words is "three billion, one hundred thirty million, two hundred fifty-four thousand, forty-one".