313043414099978 has 4 divisors (see below), whose sum is σ = 469565121149970. Its totient is φ = 156521707049988.

The previous prime is 313043414099971. The next prime is 313043414099993. The reversal of 313043414099978 is 879990414340313.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 207471960708769 + 105571453391209 = 14403887^2 + 10274797^2 .

It is a super-3 number, since 3×313043414099978³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (313043414099971) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78260853524993 + ... + 78260853524996.

Almost surely, 2^{313043414099978} is an apocalyptic number.

313043414099978 is a deficient number, since it is larger than the sum of its proper divisors (156521707049992).

313043414099978 is a wasteful number, since it uses less digits than its factorization.

313043414099978 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156521707049991.

The product of its (nonzero) digits is 70543872, while the sum is 65.

The spelling of 313043414099978 in words is "three hundred thirteen trillion, forty-three billion, four hundred fourteen million, ninety-nine thousand, nine hundred seventy-eight".