Base | Representation |
---|---|
bin | 100011100110001100001011… |
… | …1100100010100110010110000 |
3 | 1112001122020001200122200112212 |
4 | 1013030120113210110302300 |
5 | 312020012040402230222 |
6 | 3025533414042511252 |
7 | 122644413521022434 |
oct | 10714302744246260 |
9 | 1461566050580485 |
10 | 313112101211312 |
11 | 908491073554a7 |
12 | 2b14b281205528 |
13 | 105934629b0420 |
14 | 57469c6b249c4 |
15 | 262eb6e7e46e2 |
hex | 11cc617914cb0 |
313112101211312 has 80 divisors (see below), whose sum is σ = 654367480925760. Its totient is φ = 144281706003456.
The previous prime is 313112101211269. The next prime is 313112101211383. The reversal of 313112101211312 is 213112101211313.
It is a super-2 number, since 2×3131121012113122 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2108865014 + ... + 2109013482.
It is an arithmetic number, because the mean of its divisors is an integer number (8179593511572).
Almost surely, 2313112101211312 is an apocalyptic number.
It is an amenable number.
313112101211312 is an abundant number, since it is smaller than the sum of its proper divisors (341255379714448).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
313112101211312 is a wasteful number, since it uses less digits than its factorization.
313112101211312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 164670 (or 164664 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 23.
Adding to 313112101211312 its reverse (213112101211313), we get a palindrome (526224202422625).
Subtracting from 313112101211312 its reverse (213112101211313), we obtain a palindrome (99999999999999).
The spelling of 313112101211312 in words is "three hundred thirteen trillion, one hundred twelve billion, one hundred one million, two hundred eleven thousand, three hundred twelve".
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