Base | Representation |
---|---|
bin | 100011100110010000010101… |
… | …0000010010100110111100111 |
3 | 1112001200002000221011211001210 |
4 | 1013030200222002110313213 |
5 | 312020133302224003143 |
6 | 3025541445124122503 |
7 | 122645150206002450 |
oct | 10714405202246747 |
9 | 1461602027154053 |
10 | 313121001000423 |
11 | 90851964020810 |
12 | 2b150b45836433 |
13 | 10594250774c25 |
14 | 57471ccad2127 |
15 | 262eee0cc9033 |
hex | 11cc82a094de7 |
313121001000423 has 16 divisors (see below), whose sum is σ = 520512832832256. Its totient is φ = 162660260259840.
The previous prime is 313121001000421. The next prime is 313121001000433. The reversal of 313121001000423 is 324000100121313.
It is not a de Polignac number, because 313121001000423 - 21 = 313121001000421 is a prime.
It is a super-2 number, since 2×3131210010004232 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 313121001000423.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (313121001000421) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 677751084186 + ... + 677751084647.
It is an arithmetic number, because the mean of its divisors is an integer number (32532052052016).
Almost surely, 2313121001000423 is an apocalyptic number.
313121001000423 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
313121001000423 is a deficient number, since it is larger than the sum of its proper divisors (207391831831833).
313121001000423 is a wasteful number, since it uses less digits than its factorization.
313121001000423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1355502168854.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 313121001000423 its reverse (324000100121313), we get a palindrome (637121101121736).
The spelling of 313121001000423 in words is "three hundred thirteen trillion, one hundred twenty-one billion, one million, four hundred twenty-three", and thus it is an aban number.
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