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31312110213000 = 23325337137686353
BaseRepresentation
bin1110001111010011010110…
…01101001101011110001000
311002212102000210112202212200
413013221223031031132020
513101004200203304000
6150332330154440200
76411140165234211
oct707515315153610
9132772023482780
1031312110213000
119a82433a01541
1236185b6433060
1314619474794a6
147a372b042408
15394776e90500
hex1c7a6b34d788

31312110213000 has 384 divisors, whose sum is σ = 109488892237920. Its totient is φ = 8064910540800.

The previous prime is 31312110212993. The next prime is 31312110213019. The reversal of 31312110213000 is 31201121313.

31312110213000 is a `hidden beast` number, since 3 + 131 + 211 + 0 + 21 + 300 + 0 = 666.

It can be written as a sum of positive squares in 16 ways, for example, as 1608062392836 + 29704047820164 = 1268094^2 + 5450142^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 45277824 + ... + 45964176.

Almost surely, 231312110213000 is an apocalyptic number.

31312110213000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31312110213000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (54744446118960).

31312110213000 is an abundant number, since it is smaller than the sum of its proper divisors (78176782024920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31312110213000 is a wasteful number, since it uses less digits than its factorization.

31312110213000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 686554 (or 686537 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 31312110213000 its reverse (31201121313), we get a palindrome (31343311334313).

The spelling of 31312110213000 in words is "thirty-one trillion, three hundred twelve billion, one hundred ten million, two hundred thirteen thousand".