Base | Representation |
---|---|
bin | 1110001111010011010110… |
… | …10001010110111000100101 |
3 | 11002212102000212121000010212 |
4 | 13013221223101112320211 |
5 | 13101004200443101013 |
6 | 150332330234025205 |
7 | 6411140210412536 |
oct | 707515321267045 |
9 | 132772025530125 |
10 | 31312111300133 |
11 | 9a824345842a4 |
12 | 36185b6878205 |
13 | 146194776a271 |
14 | 7a372b24668d |
15 | 3947771076a8 |
hex | 1c7a6b456e25 |
31312111300133 has 4 divisors (see below), whose sum is σ = 31312176838668. Its totient is φ = 31312045761600.
The previous prime is 31312111300117. The next prime is 31312111300139. The reversal of 31312111300133 is 33100311121313.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9751486371169 + 21560624928964 = 3122737^2 + 4643342^2 .
It is a cyclic number.
It is not a de Polignac number, because 31312111300133 - 24 = 31312111300117 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 31312111300099 and 31312111300108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31312111300139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32047316 + ... + 33009917.
It is an arithmetic number, because the mean of its divisors is an integer number (7828044209667).
Almost surely, 231312111300133 is an apocalyptic number.
It is an amenable number.
31312111300133 is a deficient number, since it is larger than the sum of its proper divisors (65538535).
31312111300133 is an equidigital number, since it uses as much as digits as its factorization.
31312111300133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65538534.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 31312111300133 its reverse (33100311121313), we get a palindrome (64412422421446).
It can be divided in two parts, 3131211 and 1300133, that added together give a palindrome (4431344).
The spelling of 31312111300133 in words is "thirty-one trillion, three hundred twelve billion, one hundred eleven million, three hundred thousand, one hundred thirty-three".
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