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313123010042 = 2156561505021
BaseRepresentation
bin1001000111001111001…
…01011111010111111010
31002221020002012000021002
410203213211133113322
520112233442310132
6355502520445002
731423323446003
oct4434745372772
91087202160232
10313123010042
11110881859a47
1250828319762
13236b183c5cb
1411225d6c1aa
15822980d262
hex48e795f5fa

313123010042 has 4 divisors (see below), whose sum is σ = 469684515066. Its totient is φ = 156561505020.

The previous prime is 313123010003. The next prime is 313123010069. The reversal of 313123010042 is 240010321313.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 240010321313 = 734287188759.

It can be written as a sum of positive squares in only one way, i.e., 301553641321 + 11569368721 = 549139^2 + 107561^2 .

It is a junction number, because it is equal to n+sod(n) for n = 313123009996 and 313123010023.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78280752509 + ... + 78280752512.

Almost surely, 2313123010042 is an apocalyptic number.

313123010042 is a deficient number, since it is larger than the sum of its proper divisors (156561505024).

313123010042 is a wasteful number, since it uses less digits than its factorization.

313123010042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156561505023.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 313123010042 its reverse (240010321313), we get a palindrome (553133331355).

The spelling of 313123010042 in words is "three hundred thirteen billion, one hundred twenty-three million, ten thousand, forty-two".

Divisors: 1 2 156561505021 313123010042