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313130132112002 = 2156565066056001
BaseRepresentation
bin100011100110010100100101…
…0010010110000001010000010
31112001200221121021222100100112
41013030221022102300022002
5312020311002310041002
63025545555151351322
7122645622403114142
oct10714511222601202
91461627537870315
10313130132112002
119085581a323017
122b152873822542
131059507743c92a
1457478176b6922
152630377753852
hex11cca4a4b0282

313130132112002 has 4 divisors (see below), whose sum is σ = 469695198168006. Its totient is φ = 156565066056000.

The previous prime is 313130132111987. The next prime is 313130132112019. The reversal of 313130132112002 is 200211231031313.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 218724015641041 + 94406116470961 = 14789321^2 + 9716281^2 .

It is a super-2 number, since 2×3131301321120022 (a number of 30 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78282533027999 + ... + 78282533028002.

Almost surely, 2313130132112002 is an apocalyptic number.

313130132112002 is a deficient number, since it is larger than the sum of its proper divisors (156565066056004).

313130132112002 is a wasteful number, since it uses less digits than its factorization.

313130132112002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156565066056003.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 313130132112002 its reverse (200211231031313), we get a palindrome (513341363143315).

The spelling of 313130132112002 in words is "three hundred thirteen trillion, one hundred thirty billion, one hundred thirty-two million, one hundred twelve thousand, two".

Divisors: 1 2 156565066056001 313130132112002