313200102220133 has 4 divisors (see below), whose sum is σ = 313269409616160. Its totient is φ = 313130794824108.

The previous prime is 313200102220043. The next prime is 313200102220141. The reversal of 313200102220133 is 331022201002313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 313200102220133 - 2²⁰ = 313200101171557 is a prime.

It is a super-3 number, since 3×313200102220133³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 313200102220099 and 313200102220108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (313200102220183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34653691235 + ... + 34653700272.

It is an arithmetic number, because the mean of its divisors is an integer number (78317352404040).

Almost surely, 2^{313200102220133} is an apocalyptic number.

It is an amenable number.

313200102220133 is a deficient number, since it is larger than the sum of its proper divisors (69307396027).

313200102220133 is an equidigital number, since it uses as much as digits as its factorization.

313200102220133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69307396026.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 313200102220133 its reverse (331022201002313), we get a palindrome (644222303222446).

The spelling of 313200102220133 in words is "three hundred thirteen trillion, two hundred billion, one hundred two million, two hundred twenty thousand, one hundred thirty-three".