313202340111431 has 4 divisors (see below), whose sum is σ = 317166926695200. Its totient is φ = 309237753527664.

The previous prime is 313202340111389. The next prime is 313202340111457. The reversal of 313202340111431 is 134111043202313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 313202340111431 - 2⁴⁶ = 242833595933767 is a prime.

It is a super-3 number, since 3×313202340111431³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 313202340111394 and 313202340111403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (313202340111491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1982293291766 + ... + 1982293291923.

It is an arithmetic number, because the mean of its divisors is an integer number (79291731673800).

Almost surely, 2^{313202340111431} is an apocalyptic number.

313202340111431 is a deficient number, since it is larger than the sum of its proper divisors (3964586583769).

313202340111431 is an equidigital number, since it uses as much as digits as its factorization.

313202340111431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3964586583768.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 313202340111431 its reverse (134111043202313), we get a palindrome (447313383313744).

The spelling of 313202340111431 in words is "three hundred thirteen trillion, two hundred two billion, three hundred forty million, one hundred eleven thousand, four hundred thirty-one".