Base | Representation |
---|---|
bin | 100011100110111010110000… |
… | …1101111110111110010000100 |
3 | 1112001222210020212110122110102 |
4 | 1013031311201233313302010 |
5 | 312023131420240000004 |
6 | 3030051355514543232 |
7 | 122654554364503124 |
oct | 10715654157676204 |
9 | 1461883225418412 |
10 | 313212130000004 |
11 | 90887577a63a04 |
12 | 2b166738737b18 |
13 | 1059ca1445c6a1 |
14 | 574b79591ac84 |
15 | 263257631911e |
hex | 11cdd61bf7c84 |
313212130000004 has 6 divisors (see below), whose sum is σ = 548121227500014. Its totient is φ = 156606065000000.
The previous prime is 313212129999961. The next prime is 313212130000057. The reversal of 313212130000004 is 400000031212313.
It can be written as a sum of positive squares in only one way, i.e., 256491499683904 + 56720630316100 = 16015352^2 + 7531310^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39151516249997 + ... + 39151516250004.
It is an arithmetic number, because the mean of its divisors is an integer number (91353537916669).
Almost surely, 2313212130000004 is an apocalyptic number.
It is an amenable number.
313212130000004 is a deficient number, since it is larger than the sum of its proper divisors (234909097500010).
313212130000004 is a wasteful number, since it uses less digits than its factorization.
313212130000004 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78303032500005 (or 78303032500003 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 313212130000004 its reverse (400000031212313), we get a palindrome (713212161212317).
The spelling of 313212130000004 in words is "three hundred thirteen trillion, two hundred twelve billion, one hundred thirty million, four", and thus it is an aban number.
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