Base | Representation |
---|---|
bin | 101101100101001000100… |
… | …000000111010000000001 |
3 | 102002102212201100012201202 |
4 | 231211020200013100001 |
5 | 402304320332133031 |
6 | 10354533515110545 |
7 | 442204004525306 |
oct | 55451040072001 |
9 | 12072781305652 |
10 | 3132247536641 |
11 | aa8419093403 |
12 | 427073442455 |
13 | 1994a623b172 |
14 | ab85ca950ad |
15 | 56724a642cb |
hex | 2d948807401 |
3132247536641 has 4 divisors (see below), whose sum is σ = 3185336478000. Its totient is φ = 3079158595284.
The previous prime is 3132247536553. The next prime is 3132247536659. The reversal of 3132247536641 is 1466357422313.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3132247536641 - 226 = 3132180427777 is a prime.
It is a super-2 number, since 2×31322475366412 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3132247536941) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26544470591 + ... + 26544470708.
It is an arithmetic number, because the mean of its divisors is an integer number (796334119500).
Almost surely, 23132247536641 is an apocalyptic number.
It is an amenable number.
3132247536641 is a deficient number, since it is larger than the sum of its proper divisors (53088941359).
3132247536641 is an equidigital number, since it uses as much as digits as its factorization.
3132247536641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53088941358.
The product of its digits is 2177280, while the sum is 47.
The spelling of 3132247536641 in words is "three trillion, one hundred thirty-two billion, two hundred forty-seven million, five hundred thirty-six thousand, six hundred forty-one".
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